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how does RE# find the leftmost-longest match efficiently? remember the bidirectional scanning we mentioned earlier - run the DFA right to left to find all possible match starts, then run a reversed DFA left to right to find the ends. the leftmost start paired with the rightmost end gives you leftmost-longest. two linear DFA scans, no backtracking, no ambiguity.,更多细节参见快连下载安装
int getMaxDigits(int arr[], int n) {,更多细节参见电影
Other than how to better prompt the AI and the sort of failures to routinely expect? No.,这一点在PDF资料中也有详细论述
[&:first-child]:overflow-hidden [&:first-child]:max-h-full"